5x=40x^-1/2

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Solution for 5x=40x^-1/2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

5*x = (40*x^-1)/2 // - (40*x^-1)/2

5*x-((40*x^-1)/2) = 0

5*x-20*x^-1 = 0

5*x^1-20*x^-1 = 0

(5*x^2-20*x^0)/(x^1) = 0 // * x^2

x^1*(5*x^2-20*x^0) = 0

x^1

5*x^2-20 = 0

5*x^2-20 = 0

DELTA = 0^2-(-20*4*5)

DELTA = 400

DELTA > 0

x = (400^(1/2)+0)/(2*5) or x = (0-400^(1/2))/(2*5)

x = 2 or x = -2

x in { -2, 2} 

x in { -2, 2 }

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